4(2x-3)+5(2-x)=6(1-x)+5x

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Solution for 4(2x-3)+5(2-x)=6(1-x)+5x equation: 



4(2x-3)+5(2-x)=6(1-x)+5x

We move all terms to the left:

4(2x-3)+5(2-x)-(6(1-x)+5x)=0

We add all the numbers together, and all the variables

4(2x-3)+5(-1x+2)-(6(-1x+1)+5x)=0

We multiply parentheses

8x-5x-(6(-1x+1)+5x)-12+10=0



We calculate terms in parentheses: -(6(-1x+1)+5x), so:

6(-1x+1)+5x

We add all the numbers together, and all the variables

5x+6(-1x+1)

We multiply parentheses

5x-6x+6

We add all the numbers together, and all the variables

-1x+6

Back to the equation:

-(-1x+6)



We add all the numbers together, and all the variables

3x-(-1x+6)-2=0

We get rid of parentheses

3x+1x-6-2=0

We add all the numbers together, and all the variables

4x-8=0

We move all terms containing x to the left, all other terms to the right

4x=8

x=8/4

x=2

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