4(2x-3)+5=6(3x+2)

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Solution for 4(2x-3)+5=6(3x+2) equation: 



4(2x-3)+5=6(3x+2)

We move all terms to the left:

4(2x-3)+5-(6(3x+2))=0

We multiply parentheses

8x-(6(3x+2))-12+5=0



We calculate terms in parentheses: -(6(3x+2)), so:

6(3x+2)

We multiply parentheses

18x+12

Back to the equation:

-(18x+12)



We add all the numbers together, and all the variables

8x-(18x+12)-7=0

We get rid of parentheses

8x-18x-12-7=0

We add all the numbers together, and all the variables

-10x-19=0

We move all terms containing x to the left, all other terms to the right

-10x=19

x=19/-10

x=-1+9/10

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