4(2x-3)+7=2(1-x)+8

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Solution for 4(2x-3)+7=2(1-x)+8 equation: 



4(2x-3)+7=2(1-x)+8

We move all terms to the left:

4(2x-3)+7-(2(1-x)+8)=0

We add all the numbers together, and all the variables

4(2x-3)-(2(-1x+1)+8)+7=0

We multiply parentheses

8x-(2(-1x+1)+8)-12+7=0



We calculate terms in parentheses: -(2(-1x+1)+8), so:

2(-1x+1)+8

We multiply parentheses

-2x+2+8

We add all the numbers together, and all the variables

-2x+10

Back to the equation:

-(-2x+10)



We add all the numbers together, and all the variables

8x-(-2x+10)-5=0

We get rid of parentheses

8x+2x-10-5=0

We add all the numbers together, and all the variables

10x-15=0

We move all terms containing x to the left, all other terms to the right

10x=15

x=15/10

x=1+1/2

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