4(2x-3)+8(x-4)=2(2x-6)

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Solution for 4(2x-3)+8(x-4)=2(2x-6) equation: 



4(2x-3)+8(x-4)=2(2x-6)

We move all terms to the left:

4(2x-3)+8(x-4)-(2(2x-6))=0

We multiply parentheses

8x+8x-(2(2x-6))-12-32=0



We calculate terms in parentheses: -(2(2x-6)), so:

2(2x-6)

We multiply parentheses

4x-12

Back to the equation:

-(4x-12)



We add all the numbers together, and all the variables

16x-(4x-12)-44=0

We get rid of parentheses

16x-4x+12-44=0

We add all the numbers together, and all the variables

12x-32=0

We move all terms containing x to the left, all other terms to the right

12x=32

x=32/12

x=2+2/3

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