4(2x-3)+8-2x=3(6x+2)

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Solution for 4(2x-3)+8-2x=3(6x+2) equation: 



4(2x-3)+8-2x=3(6x+2)

We move all terms to the left:

4(2x-3)+8-2x-(3(6x+2))=0

We add all the numbers together, and all the variables

-2x+4(2x-3)-(3(6x+2))+8=0

We multiply parentheses

-2x+8x-(3(6x+2))-12+8=0



We calculate terms in parentheses: -(3(6x+2)), so:

3(6x+2)

We multiply parentheses

18x+6

Back to the equation:

-(18x+6)



We add all the numbers together, and all the variables

6x-(18x+6)-4=0

We get rid of parentheses

6x-18x-6-4=0

We add all the numbers together, and all the variables

-12x-10=0

We move all terms containing x to the left, all other terms to the right

-12x=10

x=10/-12

x=-5/6

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