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4(2x-3)+8-2x=3(6x+2)
We move all terms to the left:
4(2x-3)+8-2x-(3(6x+2))=0
We add all the numbers together, and all the variables
-2x+4(2x-3)-(3(6x+2))+8=0
We multiply parentheses
-2x+8x-(3(6x+2))-12+8=0
We calculate terms in parentheses: -(3(6x+2)), so:We add all the numbers together, and all the variables
3(6x+2)
We multiply parentheses
18x+6
Back to the equation:
-(18x+6)
6x-(18x+6)-4=0
We get rid of parentheses
6x-18x-6-4=0
We add all the numbers together, and all the variables
-12x-10=0
We move all terms containing x to the left, all other terms to the right
-12x=10
x=10/-12
x=-5/6
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