If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4(2x-3)+8=28
We move all terms to the left:
4(2x-3)+8-(28)=0
We add all the numbers together, and all the variables
4(2x-3)-20=0
We multiply parentheses
8x-12-20=0
We add all the numbers together, and all the variables
8x-32=0
We move all terms containing x to the left, all other terms to the right
8x=32
x=32/8
x=4
| 21w+70÷3=-4 | | (21w+70)÷3=-4 | | 7(3w+10)÷3=-4 | | 4(2x/3=8)40 | | (2p)p=6 | | 6=r5 | | 5+2x=-1+x | | 33 = s/3 | | 3x+5x–6x=2x | | 32=6-13x | | 7(5-x)=-4(x-11)) | | 30x-5=20x+45 | | 3x-12=1/2x | | 7-2x=1+4x-6x | | -2x-2+1=5 | | 3x3-5=70 | | 5-8x=-10x-7 | | 3x+9=-29 | | 15g+3=11g+27 | | 0,4⋅(x+2)−0,1⋅(3x+4)=0 | | 2(l+3)=-4 | | 3c-6=5c+5 | | 35x+25=47x-119 | | 5x+11,3=3x+15,3 | | 39(5x-2)=2(2x+1) | | 8+6x=-6x-5 | | 10m-26=74m= | | 7+11x=183 | | 100+2x+x+47=360 | | x+16+118+134+x=360 | | 3(x-7)/4=-9 | | (8r^2-7r-9)+(-r^2+r)=(8r2−7r−9)+(−r2+r) |