4(2x-3)-3(x-4)+x=6

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Solution for 4(2x-3)-3(x-4)+x=6 equation: 



4(2x-3)-3(x-4)+x=6

We move all terms to the left:

4(2x-3)-3(x-4)+x-(6)=0

We add all the numbers together, and all the variables

x+4(2x-3)-3(x-4)-6=0

We multiply parentheses

x+8x-3x-12+12-6=0

We add all the numbers together, and all the variables

6x-6=0

We move all terms containing x to the left, all other terms to the right

6x=6

x=6/6

x=1

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