4(2x-3)-3=4(x-2)+1

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Solution for 4(2x-3)-3=4(x-2)+1 equation: 



4(2x-3)-3=4(x-2)+1

We move all terms to the left:

4(2x-3)-3-(4(x-2)+1)=0

We multiply parentheses

8x-(4(x-2)+1)-12-3=0



We calculate terms in parentheses: -(4(x-2)+1), so:

4(x-2)+1

We multiply parentheses

4x-8+1

We add all the numbers together, and all the variables

4x-7

Back to the equation:

-(4x-7)



We add all the numbers together, and all the variables

8x-(4x-7)-15=0

We get rid of parentheses

8x-4x+7-15=0

We add all the numbers together, and all the variables

4x-8=0

We move all terms containing x to the left, all other terms to the right

4x=8

x=8/4

x=2

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