4(2x-3)-5=6(3-x)-7

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Solution for 4(2x-3)-5=6(3-x)-7 equation: 



4(2x-3)-5=6(3-x)-7

We move all terms to the left:

4(2x-3)-5-(6(3-x)-7)=0

We add all the numbers together, and all the variables

4(2x-3)-(6(-1x+3)-7)-5=0

We multiply parentheses

8x-(6(-1x+3)-7)-12-5=0



We calculate terms in parentheses: -(6(-1x+3)-7), so:

6(-1x+3)-7

We multiply parentheses

-6x+18-7

We add all the numbers together, and all the variables

-6x+11

Back to the equation:

-(-6x+11)



We add all the numbers together, and all the variables

8x-(-6x+11)-17=0

We get rid of parentheses

8x+6x-11-17=0

We add all the numbers together, and all the variables

14x-28=0

We move all terms containing x to the left, all other terms to the right

14x=28

x=28/14

x=2

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