4(2x-3)-8=5(x+3)+10

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Solution for 4(2x-3)-8=5(x+3)+10 equation: 



4(2x-3)-8=5(x+3)+10

We move all terms to the left:

4(2x-3)-8-(5(x+3)+10)=0

We multiply parentheses

8x-(5(x+3)+10)-12-8=0



We calculate terms in parentheses: -(5(x+3)+10), so:

5(x+3)+10

We multiply parentheses

5x+15+10

We add all the numbers together, and all the variables

5x+25

Back to the equation:

-(5x+25)



We add all the numbers together, and all the variables

8x-(5x+25)-20=0

We get rid of parentheses

8x-5x-25-20=0

We add all the numbers together, and all the variables

3x-45=0

We move all terms containing x to the left, all other terms to the right

3x=45

x=45/3

x=15

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