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4(2x-3)/2=3(3x+2)/4
We move all terms to the left:
4(2x-3)/2-(3(3x+2)/4)=0
We calculate fractions
8x/()+(-(3(3x+2)*2)/()=0
We calculate terms in parentheses: +(-(3(3x+2)*2)/(), so:We get rid of parentheses
-(3(3x+2)*2)/(
We multiply all the terms by the denominator
-(3(3x+2)*2)
We calculate terms in parentheses: -(3(3x+2)*2), so:We get rid of parentheses
3(3x+2)*2
We multiply parentheses
18x+12
Back to the equation:
-(18x+12)
-18x-12
Back to the equation:
+(-18x-12)
8x/()-18x-12=0
We multiply all the terms by the denominator
8x-18x*()-12*()=0
We add all the numbers together, and all the variables
8x-18x*()=0
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