4(2x-3)8(x-4)=2(2x+6)

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Solution for 4(2x-3)8(x-4)=2(2x+6) equation: 



4(2x-3)8(x-4)=2(2x+6)

We move all terms to the left:

4(2x-3)8(x-4)-(2(2x+6))=0



We calculate terms in parentheses: -(2(2x+6)), so:

2(2x+6)

We multiply parentheses

4x+12

Back to the equation:

-(4x+12)



We get rid of parentheses

4(2x-3)8(x-4)-4x-12=0

We add all the numbers together, and all the variables

-4x+4(2x-3)8(x-4)-12=0

We move all terms containing x to the left, all other terms to the right

-4x+4(2x-3)8(x-4)=12

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