4(2x-3)=-7(x+1)

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Solution for 4(2x-3)=-7(x+1) equation: 



4(2x-3)=-7(x+1)

We move all terms to the left:

4(2x-3)-(-7(x+1))=0

We multiply parentheses

8x-(-7(x+1))-12=0



We calculate terms in parentheses: -(-7(x+1)), so:

-7(x+1)

We multiply parentheses

-7x-7

Back to the equation:

-(-7x-7)



We get rid of parentheses

8x+7x+7-12=0

We add all the numbers together, and all the variables

15x-5=0

We move all terms containing x to the left, all other terms to the right

15x=5

x=5/15

x=1/3

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