4(2x-3)=16x+40

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Solution for 4(2x-3)=16x+40 equation: 



4(2x-3)=16x+40

We move all terms to the left:

4(2x-3)-(16x+40)=0

We multiply parentheses

8x-(16x+40)-12=0

We get rid of parentheses

8x-16x-40-12=0

We add all the numbers together, and all the variables

-8x-52=0

We move all terms containing x to the left, all other terms to the right

-8x=52

x=52/-8

x=-6+1/2

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