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4(2x-3)=2(x+1)+4
We move all terms to the left:
4(2x-3)-(2(x+1)+4)=0
We multiply parentheses
8x-(2(x+1)+4)-12=0
We calculate terms in parentheses: -(2(x+1)+4), so:We get rid of parentheses
2(x+1)+4
We multiply parentheses
2x+2+4
We add all the numbers together, and all the variables
2x+6
Back to the equation:
-(2x+6)
8x-2x-6-12=0
We add all the numbers together, and all the variables
6x-18=0
We move all terms containing x to the left, all other terms to the right
6x=18
x=18/6
x=3
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