4(2x-3)=20+6x

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Solution for 4(2x-3)=20+6x equation: 



4(2x-3)=20+6x

We move all terms to the left:

4(2x-3)-(20+6x)=0

We add all the numbers together, and all the variables

4(2x-3)-(6x+20)=0

We multiply parentheses

8x-(6x+20)-12=0

We get rid of parentheses

8x-6x-20-12=0

We add all the numbers together, and all the variables

2x-32=0

We move all terms containing x to the left, all other terms to the right

2x=32

x=32/2

x=16

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