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4(2x-3)=2x+3(2x+4)
We move all terms to the left:
4(2x-3)-(2x+3(2x+4))=0
We multiply parentheses
8x-(2x+3(2x+4))-12=0
We calculate terms in parentheses: -(2x+3(2x+4)), so:We get rid of parentheses
2x+3(2x+4)
We multiply parentheses
2x+6x+12
We add all the numbers together, and all the variables
8x+12
Back to the equation:
-(8x+12)
8x-8x-12-12=0
We add all the numbers together, and all the variables
-24!=0
There is no solution for this equation
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