4(2x-3)=5(x+3)0

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Solution for 4(2x-3)=5(x+3)0 equation: 



4(2x-3)=5(x+3)0

We move all terms to the left:

4(2x-3)-(5(x+3)0)=0

We multiply parentheses

8x-(5(x+3)0)-12=0



We calculate terms in parentheses: -(5(x+3)0), so:

5(x+3)0

We multiply parentheses

5x+15

Back to the equation:

-(5x+15)



We get rid of parentheses

8x-5x-15-12=0

We add all the numbers together, and all the variables

3x-27=0

We move all terms containing x to the left, all other terms to the right

3x=27

x=27/3

x=9

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