4(2x-3)=5-2(x+1)

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Solution for 4(2x-3)=5-2(x+1) equation: 



4(2x-3)=5-2(x+1)

We move all terms to the left:

4(2x-3)-(5-2(x+1))=0

We multiply parentheses

8x-(5-2(x+1))-12=0



We calculate terms in parentheses: -(5-2(x+1)), so:

5-2(x+1)

determiningTheFunctionDomain
-2(x+1)+5

We multiply parentheses

-2x-2+5

We add all the numbers together, and all the variables

-2x+3

Back to the equation:

-(-2x+3)



We get rid of parentheses

8x+2x-3-12=0

We add all the numbers together, and all the variables

10x-15=0

We move all terms containing x to the left, all other terms to the right

10x=15

x=15/10

x=1+1/2

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