4(2x-3)=6(x-2)

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Solution for 4(2x-3)=6(x-2) equation: 



4(2x-3)=6(x-2)

We move all terms to the left:

4(2x-3)-(6(x-2))=0

We multiply parentheses

8x-(6(x-2))-12=0



We calculate terms in parentheses: -(6(x-2)), so:

6(x-2)

We multiply parentheses

6x-12

Back to the equation:

-(6x-12)



We get rid of parentheses

8x-6x+12-12=0

We add all the numbers together, and all the variables

2x=0

x=0/2

x=0

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