4(2x-3)=7(x-2)+x

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Solution for 4(2x-3)=7(x-2)+x equation: 


Simplifying
4(2x + -3) = 7(x + -2) + x

Reorder the terms:
4(-3 + 2x) = 7(x + -2) + x
(-3 * 4 + 2x * 4) = 7(x + -2) + x
(-12 + 8x) = 7(x + -2) + x

Reorder the terms:
-12 + 8x = 7(-2 + x) + x
-12 + 8x = (-2 * 7 + x * 7) + x
-12 + 8x = (-14 + 7x) + x

Combine like terms: 7x + x = 8x
-12 + 8x = -14 + 8x

Add '-8x' to each side of the equation.
-12 + 8x + -8x = -14 + 8x + -8x

Combine like terms: 8x + -8x = 0
-12 + 0 = -14 + 8x + -8x
-12 = -14 + 8x + -8x

Combine like terms: 8x + -8x = 0
-12 = -14 + 0
-12 = -14

Solving
-12 = -14

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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