4(2x-3)=7+3(x+1)

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Solution for 4(2x-3)=7+3(x+1) equation: 



4(2x-3)=7+3(x+1)

We move all terms to the left:

4(2x-3)-(7+3(x+1))=0

We multiply parentheses

8x-(7+3(x+1))-12=0



We calculate terms in parentheses: -(7+3(x+1)), so:

7+3(x+1)

determiningTheFunctionDomain
3(x+1)+7

We multiply parentheses

3x+3+7

We add all the numbers together, and all the variables

3x+10

Back to the equation:

-(3x+10)



We get rid of parentheses

8x-3x-10-12=0

We add all the numbers together, and all the variables

5x-22=0

We move all terms containing x to the left, all other terms to the right

5x=22

x=22/5

x=4+2/5

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