4(2x-3)=8(x-2)

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Solution for 4(2x-3)=8(x-2) equation:


Simplifying
4(2x + -3) = 8(x + -2)

Reorder the terms:
4(-3 + 2x) = 8(x + -2)
(-3 * 4 + 2x * 4) = 8(x + -2)
(-12 + 8x) = 8(x + -2)

Reorder the terms:
-12 + 8x = 8(-2 + x)
-12 + 8x = (-2 * 8 + x * 8)
-12 + 8x = (-16 + 8x)

Add '-8x' to each side of the equation.
-12 + 8x + -8x = -16 + 8x + -8x

Combine like terms: 8x + -8x = 0
-12 + 0 = -16 + 8x + -8x
-12 = -16 + 8x + -8x

Combine like terms: 8x + -8x = 0
-12 = -16 + 0
-12 = -16

Solving
-12 = -16

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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