4(2x-3)=x+15-6x+12

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Solution for 4(2x-3)=x+15-6x+12 equation: 



4(2x-3)=x+15-6x+12

We move all terms to the left:

4(2x-3)-(x+15-6x+12)=0

We add all the numbers together, and all the variables

4(2x-3)-(-5x+27)=0

We multiply parentheses

8x-(-5x+27)-12=0

We get rid of parentheses

8x+5x-27-12=0

We add all the numbers together, and all the variables

13x-39=0

We move all terms containing x to the left, all other terms to the right

13x=39

x=39/13

x=3

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