4(2x-4)+17=3(2+x)-20

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Solution for 4(2x-4)+17=3(2+x)-20 equation: 



4(2x-4)+17=3(2+x)-20

We move all terms to the left:

4(2x-4)+17-(3(2+x)-20)=0

We add all the numbers together, and all the variables

4(2x-4)-(3(x+2)-20)+17=0

We multiply parentheses

8x-(3(x+2)-20)-16+17=0



We calculate terms in parentheses: -(3(x+2)-20), so:

3(x+2)-20

We multiply parentheses

3x+6-20

We add all the numbers together, and all the variables

3x-14

Back to the equation:

-(3x-14)



We add all the numbers together, and all the variables

8x-(3x-14)+1=0

We get rid of parentheses

8x-3x+14+1=0

We add all the numbers together, and all the variables

5x+15=0

We move all terms containing x to the left, all other terms to the right

5x=-15

x=-15/5

x=-3

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