4(2x-4)+2=4(x-2)

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Solution for 4(2x-4)+2=4(x-2) equation: 



4(2x-4)+2=4(x-2)

We move all terms to the left:

4(2x-4)+2-(4(x-2))=0

We multiply parentheses

8x-(4(x-2))-16+2=0



We calculate terms in parentheses: -(4(x-2)), so:

4(x-2)

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)



We add all the numbers together, and all the variables

8x-(4x-8)-14=0

We get rid of parentheses

8x-4x+8-14=0

We add all the numbers together, and all the variables

4x-6=0

We move all terms containing x to the left, all other terms to the right

4x=6

x=6/4

x=1+1/2

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