4(2x-4)+3x=32

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Solution for 4(2x-4)+3x=32 equation: 



4(2x-4)+3x=32

We move all terms to the left:

4(2x-4)+3x-(32)=0

We add all the numbers together, and all the variables

3x+4(2x-4)-32=0

We multiply parentheses

3x+8x-16-32=0

We add all the numbers together, and all the variables

11x-48=0

We move all terms containing x to the left, all other terms to the right

11x=48

x=48/11

x=4+4/11

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