4(2x-4)-4(5x+3)=4-3(x+2)

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Solution for 4(2x-4)-4(5x+3)=4-3(x+2) equation: 



4(2x-4)-4(5x+3)=4-3(x+2)

We move all terms to the left:

4(2x-4)-4(5x+3)-(4-3(x+2))=0

We multiply parentheses

8x-20x-(4-3(x+2))-16-12=0



We calculate terms in parentheses: -(4-3(x+2)), so:

4-3(x+2)

determiningTheFunctionDomain
-3(x+2)+4

We multiply parentheses

-3x-6+4

We add all the numbers together, and all the variables

-3x-2

Back to the equation:

-(-3x-2)



We add all the numbers together, and all the variables

-12x-(-3x-2)-28=0

We get rid of parentheses

-12x+3x+2-28=0

We add all the numbers together, and all the variables

-9x-26=0

We move all terms containing x to the left, all other terms to the right

-9x=26

x=26/-9

x=-2+8/9

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