4(2x-4)-5=4(x-4)+22

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Solution for 4(2x-4)-5=4(x-4)+22 equation: 



4(2x-4)-5=4(x-4)+22

We move all terms to the left:

4(2x-4)-5-(4(x-4)+22)=0

We multiply parentheses

8x-(4(x-4)+22)-16-5=0



We calculate terms in parentheses: -(4(x-4)+22), so:

4(x-4)+22

We multiply parentheses

4x-16+22

We add all the numbers together, and all the variables

4x+6

Back to the equation:

-(4x+6)



We add all the numbers together, and all the variables

8x-(4x+6)-21=0

We get rid of parentheses

8x-4x-6-21=0

We add all the numbers together, and all the variables

4x-27=0

We move all terms containing x to the left, all other terms to the right

4x=27

x=27/4

x=6+3/4

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