4(2x-4)=8(x-2)

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Solution for 4(2x-4)=8(x-2) equation:


Simplifying
4(2x + -4) = 8(x + -2)

Reorder the terms:
4(-4 + 2x) = 8(x + -2)
(-4 * 4 + 2x * 4) = 8(x + -2)
(-16 + 8x) = 8(x + -2)

Reorder the terms:
-16 + 8x = 8(-2 + x)
-16 + 8x = (-2 * 8 + x * 8)
-16 + 8x = (-16 + 8x)

Add '16' to each side of the equation.
-16 + 16 + 8x = -16 + 16 + 8x

Combine like terms: -16 + 16 = 0
0 + 8x = -16 + 16 + 8x
8x = -16 + 16 + 8x

Combine like terms: -16 + 16 = 0
8x = 0 + 8x
8x = 8x

Add '-8x' to each side of the equation.
8x + -8x = 8x + -8x

Combine like terms: 8x + -8x = 0
0 = 8x + -8x

Combine like terms: 8x + -8x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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