4(2x-5)+3(2x+6)=72

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Solution for 4(2x-5)+3(2x+6)=72 equation: 



4(2x-5)+3(2x+6)=72

We move all terms to the left:

4(2x-5)+3(2x+6)-(72)=0

We multiply parentheses

8x+6x-20+18-72=0

We add all the numbers together, and all the variables

14x-74=0

We move all terms containing x to the left, all other terms to the right

14x=74

x=74/14

x=5+2/7

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