4(2x-5)+3(6+3x)=100

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Solution for 4(2x-5)+3(6+3x)=100 equation: 



4(2x-5)+3(6+3x)=100

We move all terms to the left:

4(2x-5)+3(6+3x)-(100)=0

We add all the numbers together, and all the variables

4(2x-5)+3(3x+6)-100=0

We multiply parentheses

8x+9x-20+18-100=0

We add all the numbers together, and all the variables

17x-102=0

We move all terms containing x to the left, all other terms to the right

17x=102

x=102/17

x=6

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