4(2x-5)-2=4(x-3)+22

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Solution for 4(2x-5)-2=4(x-3)+22 equation: 



4(2x-5)-2=4(x-3)+22

We move all terms to the left:

4(2x-5)-2-(4(x-3)+22)=0

We multiply parentheses

8x-(4(x-3)+22)-20-2=0



We calculate terms in parentheses: -(4(x-3)+22), so:

4(x-3)+22

We multiply parentheses

4x-12+22

We add all the numbers together, and all the variables

4x+10

Back to the equation:

-(4x+10)



We add all the numbers together, and all the variables

8x-(4x+10)-22=0

We get rid of parentheses

8x-4x-10-22=0

We add all the numbers together, and all the variables

4x-32=0

We move all terms containing x to the left, all other terms to the right

4x=32

x=32/4

x=8

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