4(2x-5)-2=4(x-3)+22

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Solution for 4(2x-5)-2=4(x-3)+22 equation:



4(2x-5)-2=4(x-3)+22
We move all terms to the left:
4(2x-5)-2-(4(x-3)+22)=0
We multiply parentheses
8x-(4(x-3)+22)-20-2=0
We calculate terms in parentheses: -(4(x-3)+22), so:
4(x-3)+22
We multiply parentheses
4x-12+22
We add all the numbers together, and all the variables
4x+10
Back to the equation:
-(4x+10)
We add all the numbers together, and all the variables
8x-(4x+10)-22=0
We get rid of parentheses
8x-4x-10-22=0
We add all the numbers together, and all the variables
4x-32=0
We move all terms containing x to the left, all other terms to the right
4x=32
x=32/4
x=8

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