4(2x-5)-3(3x+1)=6(x-2)+5x

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Solution for 4(2x-5)-3(3x+1)=6(x-2)+5x equation: 



4(2x-5)-3(3x+1)=6(x-2)+5x

We move all terms to the left:

4(2x-5)-3(3x+1)-(6(x-2)+5x)=0

We multiply parentheses

8x-9x-(6(x-2)+5x)-20-3=0



We calculate terms in parentheses: -(6(x-2)+5x), so:

6(x-2)+5x

We add all the numbers together, and all the variables

5x+6(x-2)

We multiply parentheses

5x+6x-12

We add all the numbers together, and all the variables

11x-12

Back to the equation:

-(11x-12)



We add all the numbers together, and all the variables

-1x-(11x-12)-23=0

We get rid of parentheses

-1x-11x+12-23=0

We add all the numbers together, and all the variables

-12x-11=0

We move all terms containing x to the left, all other terms to the right

-12x=11

x=11/-12

x=-11/12

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