4(2x-5)-6(2x/3)=6+9(2x/3)+(2x-5)

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Solution for 4(2x-5)-6(2x/3)=6+9(2x/3)+(2x-5) equation:



4(2x-5)-6(2x/3)=6+9(2x/3)+(2x-5)
We move all terms to the left:
4(2x-5)-6(2x/3)-(6+9(2x/3)+(2x-5))=0
Domain of the equation: 3)+(2x-5))!=0
x∈R
We add all the numbers together, and all the variables
4(2x-5)-6(+2x/3)-(6+9(+2x/3)+(2x-5))=0
We multiply parentheses
8x-12x-(6+9(+2x/3)+(2x-5))-20=0
We multiply all the terms by the denominator
8x*3)+(2x-5))-12x*3)+(2x-5))-(6+9(+2x-20*3)+(2x-5))=0
We add all the numbers together, and all the variables
8x*3)+(2x-5))-12x*3)+(2x-5))-(6+9(2x-60)+(2x-5))=0
Wy multiply elements
24x^2-5))-12x*3)+(2x-5))-(6+9(2x-60)+(2x-5))=0

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