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4(2x-5)=1+x
We move all terms to the left:
4(2x-5)-(1+x)=0
We add all the numbers together, and all the variables
4(2x-5)-(x+1)=0
We multiply parentheses
8x-(x+1)-20=0
We get rid of parentheses
8x-x-1-20=0
We add all the numbers together, and all the variables
7x-21=0
We move all terms containing x to the left, all other terms to the right
7x=21
x=21/7
x=3
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