4(2x-5)=1/3(9x-6)+6

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Solution for 4(2x-5)=1/3(9x-6)+6 equation: 



4(2x-5)=1/3(9x-6)+6

We move all terms to the left:

4(2x-5)-(1/3(9x-6)+6)=0



Domain of the equation: 3(9x-6)+6)!=0

x∈R



We multiply parentheses

8x-(1/3(9x-6)+6)-20=0

We multiply all the terms by the denominator


8x*3(9x-6)-20*3(9x-6)+6)-(1+6)=0

We add all the numbers together, and all the variables

8x*3(9x-6)-20*3(9x-6)+6)-7=0

We add all the numbers together, and all the variables

8x*3(9x-6)-20*3(9x-6)=0

Wy multiply elements

24x^2(9-60x(9=0

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