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4(2x-5)=12+4x
We move all terms to the left:
4(2x-5)-(12+4x)=0
We add all the numbers together, and all the variables
4(2x-5)-(4x+12)=0
We multiply parentheses
8x-(4x+12)-20=0
We get rid of parentheses
8x-4x-12-20=0
We add all the numbers together, and all the variables
4x-32=0
We move all terms containing x to the left, all other terms to the right
4x=32
x=32/4
x=8
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