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4(2x-5)=2(6-x)
We move all terms to the left:
4(2x-5)-(2(6-x))=0
We add all the numbers together, and all the variables
4(2x-5)-(2(-1x+6))=0
We multiply parentheses
8x-(2(-1x+6))-20=0
We calculate terms in parentheses: -(2(-1x+6)), so:We get rid of parentheses
2(-1x+6)
We multiply parentheses
-2x+12
Back to the equation:
-(-2x+12)
8x+2x-12-20=0
We add all the numbers together, and all the variables
10x-32=0
We move all terms containing x to the left, all other terms to the right
10x=32
x=32/10
x=3+1/5
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