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4(2x-5)=2(x+2)
We move all terms to the left:
4(2x-5)-(2(x+2))=0
We multiply parentheses
8x-(2(x+2))-20=0
We calculate terms in parentheses: -(2(x+2)), so:We get rid of parentheses
2(x+2)
We multiply parentheses
2x+4
Back to the equation:
-(2x+4)
8x-2x-4-20=0
We add all the numbers together, and all the variables
6x-24=0
We move all terms containing x to the left, all other terms to the right
6x=24
x=24/6
x=4
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