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4(2x-5)=2(x-15)
We move all terms to the left:
4(2x-5)-(2(x-15))=0
We multiply parentheses
8x-(2(x-15))-20=0
We calculate terms in parentheses: -(2(x-15)), so:We get rid of parentheses
2(x-15)
We multiply parentheses
2x-30
Back to the equation:
-(2x-30)
8x-2x+30-20=0
We add all the numbers together, and all the variables
6x+10=0
We move all terms containing x to the left, all other terms to the right
6x=-10
x=-10/6
x=-1+2/3
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