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4(2x-5)=2(x-5)
We move all terms to the left:
4(2x-5)-(2(x-5))=0
We multiply parentheses
8x-(2(x-5))-20=0
We calculate terms in parentheses: -(2(x-5)), so:We get rid of parentheses
2(x-5)
We multiply parentheses
2x-10
Back to the equation:
-(2x-10)
8x-2x+10-20=0
We add all the numbers together, and all the variables
6x-10=0
We move all terms containing x to the left, all other terms to the right
6x=10
x=10/6
x=1+2/3
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