4(2x-5)=3(3x+2)+21

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Solution for 4(2x-5)=3(3x+2)+21 equation: 



4(2x-5)=3(3x+2)+21

We move all terms to the left:

4(2x-5)-(3(3x+2)+21)=0

We multiply parentheses

8x-(3(3x+2)+21)-20=0



We calculate terms in parentheses: -(3(3x+2)+21), so:

3(3x+2)+21

We multiply parentheses

9x+6+21

We add all the numbers together, and all the variables

9x+27

Back to the equation:

-(9x+27)



We get rid of parentheses

8x-9x-27-20=0

We add all the numbers together, and all the variables

-1x-47=0

We move all terms containing x to the left, all other terms to the right

-x=47

x=47/-1

x=-47

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