4(2x-5)=3(3x+2)+21

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Solution for 4(2x-5)=3(3x+2)+21 equation:



4(2x-5)=3(3x+2)+21
We move all terms to the left:
4(2x-5)-(3(3x+2)+21)=0
We multiply parentheses
8x-(3(3x+2)+21)-20=0
We calculate terms in parentheses: -(3(3x+2)+21), so:
3(3x+2)+21
We multiply parentheses
9x+6+21
We add all the numbers together, and all the variables
9x+27
Back to the equation:
-(9x+27)
We get rid of parentheses
8x-9x-27-20=0
We add all the numbers together, and all the variables
-1x-47=0
We move all terms containing x to the left, all other terms to the right
-x=47
x=47/-1
x=-47

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