4(2x-5)=3(5x-3)-32

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Solution for 4(2x-5)=3(5x-3)-32 equation:



4(2x-5)=3(5x-3)-32
We move all terms to the left:
4(2x-5)-(3(5x-3)-32)=0
We multiply parentheses
8x-(3(5x-3)-32)-20=0
We calculate terms in parentheses: -(3(5x-3)-32), so:
3(5x-3)-32
We multiply parentheses
15x-9-32
We add all the numbers together, and all the variables
15x-41
Back to the equation:
-(15x-41)
We get rid of parentheses
8x-15x+41-20=0
We add all the numbers together, and all the variables
-7x+21=0
We move all terms containing x to the left, all other terms to the right
-7x=-21
x=-21/-7
x=+3

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