4(2x-5)=7(x-3)

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Solution for 4(2x-5)=7(x-3) equation: 



4(2x-5)=7(x-3)

We move all terms to the left:

4(2x-5)-(7(x-3))=0

We multiply parentheses

8x-(7(x-3))-20=0



We calculate terms in parentheses: -(7(x-3)), so:

7(x-3)

We multiply parentheses

7x-21

Back to the equation:

-(7x-21)



We get rid of parentheses

8x-7x+21-20=0

We add all the numbers together, and all the variables

x+1=0

We move all terms containing x to the left, all other terms to the right

x=-1

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