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4(2x-5)=x+15
We move all terms to the left:
4(2x-5)-(x+15)=0
We multiply parentheses
8x-(x+15)-20=0
We get rid of parentheses
8x-x-15-20=0
We add all the numbers together, and all the variables
7x-35=0
We move all terms containing x to the left, all other terms to the right
7x=35
x=35/7
x=5
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