4(2x-5)=x-5(8x+3)

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Solution for 4(2x-5)=x-5(8x+3) equation: 



4(2x-5)=x-5(8x+3)

We move all terms to the left:

4(2x-5)-(x-5(8x+3))=0

We multiply parentheses

8x-(x-5(8x+3))-20=0



We calculate terms in parentheses: -(x-5(8x+3)), so:

x-5(8x+3)

We multiply parentheses

x-40x-15

We add all the numbers together, and all the variables

-39x-15

Back to the equation:

-(-39x-15)



We get rid of parentheses

8x+39x+15-20=0

We add all the numbers together, and all the variables

47x-5=0

We move all terms containing x to the left, all other terms to the right

47x=5

x=5/47

x=5/47

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