4(2x-6)-5=(x-4)+11

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Solution for 4(2x-6)-5=(x-4)+11 equation: 



4(2x-6)-5=(x-4)+11

We move all terms to the left:

4(2x-6)-5-((x-4)+11)=0

We multiply parentheses

8x-((x-4)+11)-24-5=0



We calculate terms in parentheses: -((x-4)+11), so:

(x-4)+11

We get rid of parentheses

x-4+11

We add all the numbers together, and all the variables

x+7

Back to the equation:

-(x+7)



We add all the numbers together, and all the variables

8x-(x+7)-29=0

We get rid of parentheses

8x-x-7-29=0

We add all the numbers together, and all the variables

7x-36=0

We move all terms containing x to the left, all other terms to the right

7x=36

x=36/7

x=5+1/7

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