4(2x-6)-8=32x=1

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Solution for 4(2x-6)-8=32x=1 equation: 



4(2x-6)-8=32x=1

We move all terms to the left:

4(2x-6)-8-(32x)=0

We add all the numbers together, and all the variables

-32x+4(2x-6)-8=0

We multiply parentheses

-32x+8x-24-8=0

We add all the numbers together, and all the variables

-24x-32=0

We move all terms containing x to the left, all other terms to the right

-24x=32

x=32/-24

x=-1+1/3

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