4(2x-7)-3=4(x-4)+9

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Solution for 4(2x-7)-3=4(x-4)+9 equation: 



4(2x-7)-3=4(x-4)+9

We move all terms to the left:

4(2x-7)-3-(4(x-4)+9)=0

We multiply parentheses

8x-(4(x-4)+9)-28-3=0



We calculate terms in parentheses: -(4(x-4)+9), so:

4(x-4)+9

We multiply parentheses

4x-16+9

We add all the numbers together, and all the variables

4x-7

Back to the equation:

-(4x-7)



We add all the numbers together, and all the variables

8x-(4x-7)-31=0

We get rid of parentheses

8x-4x+7-31=0

We add all the numbers together, and all the variables

4x-24=0

We move all terms containing x to the left, all other terms to the right

4x=24

x=24/4

x=6

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